Question

An astronaut approaches moon and sends a signal of frequency 5000 M Hz. The frequency of the reflected signal increases by 86 K Hz. The speed of the astronaut in Km/s will be​

Answer 1

Dear Student,

◆ Answer -

v = 2.58 km/s

● Explanation -

# Given -

n = 5000 MHz = 5×10^9 Hz

∆n = 86 KHz = 8.6×10^4 Hz

# Solution -

Let v be the speed of astronaut in the satellite -

∆n/n = 2v/c

8.6×10^4 / 5×10^9 = 2 × v / 3×10^8

v = (8.6×10^4 × 3×10^8) / (2 × 5×10^9)

v = 2.58×10^13 / 10^10

v = 2.58×10^3 m/s

v = 2.58 km/s

Hence, speed of the astronaut in km/s will be 2.58 km/s.

Thanks dear. Hope this helps you..

Answer 2

Answer:

5.16km/s

Explanation:

Plz refer image for the explanation. Thank you...