Physics, asked by amsaelangovan3875, 10 months ago

An astronaut is in a spacecraft goes into circular orbit above a straight planet that has radius of 2100 the craft is going at 1200 metre per second at an altitude of 6500 kilometre he has a life support pack that has a mass of 60 kg what will the life support pack weight on the surface of the planets

Answers

Answered by tushirakshay06
1

Answer:

Given,

Radius of the earth, R=6400km

Acceleration due to gravity, g=9.8m/s

2

When a satellite is orbitting the earth its velocity is its orbital velocity given by orbital velocity:

V

0

=

R

GM

=

g

R [∵g=

R

2

GM

]

If it has to overcome gravitational pull then its velocity should be escape velocity escape velocity V

e

=

r

2GM

=

2gR

Additional velocity required is V=V

e

−V

0

=

2gR

gR

=

gR

(

2

−1)

given that R=64004m=64×10

6

m

g=9.8m/s

2

So, additional velocity will be:

V=

gR

(

2

−1)=

9.8×6.4×10

6

(

2

−1)

⇒V=3.28×10

3

m/s

Answered by Anonymous
1

Answer:

Explanation:

Given,

Radius of the earth, R=6400km

Acceleration due to gravity, g=9.8m/s ²

When a satellite is orbitting the earth its velocity is its orbital velocity givenby orbital velocity:

V 0 = R

GM = g

R [∵g= R 2 GM ]

If it has to overcome gravitational pull then its velocity should be escape velocity escape velocity V

e = r 2GM = 2gR  

Additional velocity required is V=V

 given that R=64004m=64×10

6 m  g=9.8m/s ²

So, additional velocity will be:

V= gR

( 2 −1)= 9.8×6.4×10  6 ( 2−1)

⇒V=3.28×10

3 m/s

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