Question

An astronomical telescope has objective and eye-piece lenses of powers 0.5 d and 20 d respectively. What will be its magnifying power

Answer 1

Given, three lenses of power 0.5 D, 0.4 D and 10 D. ... Therefore, an objective with power = 0.5 D and eyepiece of power 10 D ... This choice would give a higher magnification .

Answer 2

The magnifying power of the telescope is 40.

Explanation:

It is given that,

Power of objective lens, $P_o=0.5\ D$

Power of eye piece lens, $P_e=20\ D$

Let m is the magnifying power of the astronomical telescope. It is equal to the ratio of focal length of objective to the focal length of eyepiece as :

$m=\dfrac{f_o}{f_e}$

Since, $P=\dfrac{1}{f}$

$m=\dfrac{P_e}{P_o}$

$m=\dfrac{20}{0.5}$

m = 40

So, the magnifying power of the telescope is 40. Hence, this is the required solution.

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