Question

an athelet runs along a circular track of radius 50m.find the distance travelled and the displacement of the athlete when he covers 3/4 th of the circle​

Answer 1

Answer:

Distance is 235.5

Displacement is 78.5

Explanation:

Theta=90 degree

= 90×π/180

= π/2 radian

Arc length = theta × r

= π/2 × 50

=78.5 = Displacement.

Distance = 2πr - Displacement

= ( 2×3.14×50) - 78.5

=314 - 78.5

= 235.5

Hope! I help you

Thanks...........

Answer 2

I hope this will help you ☺️