an athelet runs along a circular track of radius 50m.find the distance travelled and the displacement of the athlete when he covers 3/4 th of the circle
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Answered by
86
Distance traveled by the athlete=length of the arc
=d(theta)r
Here the athlete runs 3\4of a circle whose radius is 50 m
here, d(theta)=3(pi)/2rad
hence distance=3(pi)/2 x 50
=235.61 m
displacement=the chord between the initial point and the final point. it subtends an angle of 90degrees at the centre of the circle.
it forms a right angled triangle.
hence by Pythagoras theorem,
displacement=√50^2+50^2=70.71m
=d(theta)r
Here the athlete runs 3\4of a circle whose radius is 50 m
here, d(theta)=3(pi)/2rad
hence distance=3(pi)/2 x 50
=235.61 m
displacement=the chord between the initial point and the final point. it subtends an angle of 90degrees at the centre of the circle.
it forms a right angled triangle.
hence by Pythagoras theorem,
displacement=√50^2+50^2=70.71m
MadaraUchiha:
sorry i couldn't use the symbols like pi and theta
while you write the answers, there are some buttons/links at the bottom of the text rectangular box... click on "Omega" symbol.
displacement also has a direction... - 45 deg. to the x axis.
Answered by
18
Answer:
235.7m, 70.7
runs along the circular track of radius 50 metre find the distance travelled and displacement of the weather when he cover 3/4 of the killers
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