An athelete completes 1 round of circular track of diameter 200 m in 20 s.wat will be the distance covered and the displacement at the end of 2m 20s?
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Length of track = 2πr
=2×3.14×100
=628 m
now,at the end of 2 m 20 s, number of rounds
= (120+20)/20 = 140/20 = 7 rounds
That means he takes complete round, and reaches the starting point.
so, displacement = 0
as distance between starting and finalizing point is 0
and distance =7×628 = 4396 m
=2×3.14×100
=628 m
now,at the end of 2 m 20 s, number of rounds
= (120+20)/20 = 140/20 = 7 rounds
That means he takes complete round, and reaches the starting point.
so, displacement = 0
as distance between starting and finalizing point is 0
and distance =7×628 = 4396 m
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