Question

An Athelete covers a circular loop of radius 100 m find distance and displacement
1-in an completing 1 loop
2- in covering 1/2 of the loop
3- in covering 1/4 of the loop
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Answer 1

Answer:

radius of loop = 100m

(1)distance covered in covering 1 loop

= 2πr = 2*22/7*100 = 4400/7m

= 628.57m

displacement = 2r = 2×100 = 200m

(2) in covering 1/2 loop

distance= 628.57/2 = 314.28 m

displacement = 2r = 2(100) = 200m

(3) distance covered in covering 1/4 th loop

= 1/4*628.57 = 157.14 m

displacement = r = 100m