Question

An athelete takes 2.0 s to reach his maximum speed of 18.0 km/h. The magnitude of his average acceleration is N/2 m/s2 . Determine N.

Answer 1

Initial velocity u = 0 (∴ starts from rest) Final velocity v = 18 km/hr = 5 sec (i.e. max velocity) Time interval t = 2 sec. ∴ Acceleration = (v-u )/t = 5/2 = 2.5 m/s2.

Answer 2

                                  Answer:

                                  2.5 m/s²

                           

                              Explanation:

Initial velocity u = 0 (∴ starts from rest)

Final velocity v = 18 km/hr = 5 m/sec (i.e. max velocity)

Time interval t = 2 sec.

Therefore, Acceleration = (v-u )/t = 5/2 = 2.5 m/s².

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