An athelete takes 2.0s to reach his maximum speed of 18.0km/h.What is the magnitude of his average acceleration?
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Answered by
2
t=2 sec v=18km/hr. u=0
v=u+at
18=0+2a
a=18/2=9km/hr^2
v=u+at
18=0+2a
a=18/2=9km/hr^2
Answered by
0
Answer:
Explanation:
V=18 and u=0, t=2sec.
V=u+at
18=0+a2
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