Question

An athelete takes 20 breathes per minute at room temperature.the air inhaled in each brathe is 200ml which contains 20% o2 and exhaled air contains 10% o2 by volume.Assuming that all the oxygen is used up in converting glucose to co2 and h2o ... how much glucose is burnt in 1 hour?(room temperature-:27degrees)

Answer 1

C6H12O6 + 6O2 -----> 6CO2 + 6H2O

In one minute, volume of oxygen used= 20*200*10/100=400mL.

In one minute, volume of O2 used for combustion of glucose= 60*400=24000mL.

The number of moles of O2 consumed are=

n=PV/RT = 1*24/0.0821*300 = 0.97 = 1mL (approx. )

1 mole of glucose requires 6 mL of O2.

Hence, the number of moles of glucose that undergo combustion are 1/6.

Mass of glucose that undergoes combustion in an hour= 180/6=30g.

Lastly, heat produced is 470.4 kJ.

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