an athelete takes 2s to reach his maximam speed of 18km/h after starting from rest. what is the magnitude of his average acceleration?
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firstly, while attempting questions in physics or in any subject , try to find out the data that is given .
In this case , we have been given
u = 0 m/s ( starting from rest )
v = 18 kmph , converting it into m/s we multiply it by 5/18 we get 5m/s
t = 2 sec.
now it has asked for average acceleration i.e. equal to (v-u)/(t2-t1 )
putting in the values you get ( 5 - 0)/(2-0) = 5/2=2.5 m/s^2
I hope it helped .
drxsumit:
ok great
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