Question

An Athelete throws a Javalin to a maximum.
distance
80m. How long it is in air
to what height does it raise? neglect the height
of the
athelete ?
plzzzzz don't answer if u don't know...its important... plzzzzz don't spam!!!or else will be informed to the moderator! please answer as fast as u can​

Answer 1

Answer:

This is a case of projectile motion.

We know, the formula for the range of the projectile is u^2 sin(2theta)/g

Now, this will be maximum when sin(2theta) = 1 , that is when theta = 45°.

Now, maximum range = u^2/g = 80 m

So,

u^2 = 800

or,

u = 20√2 m/s

Now,

Time of flight = 2u sin(theta)/g

= 2*(20√2)*(1/√2)/(10) = 4 seconds

Hope this helps you !

Answer 2

Answer:

4 seconds

hope it helps u

Please follow me and mark me as brainliest and 10 thanks

please it is my humble request