an athlete can jump 3m vertically .what must be the initial velocity of the athlete?
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Answer:
7.66811m/s
Explanation:
v=0
u=?
a=-9.8m/s*2
s=3m
by 3rd law of motion
v2=u2+2as
0=u2-58.8
u=7.66811 m/s
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