Question

An athlete can jump to a maximum height of 4 m on the surface of the Earth. Considering the s initial velocity for jumping, to what height can be jump from the surface of the moon? [Take, accelera tion due to gravity on earth (gE) as 9.8 m s-2 and acceleration due to gravity on the surface of moon 1/6th of acceleration due to gravity on earth​

Answer 1

Answer:

24

Step-by-step explanation:

If the athlete jumps with same velocity = v on the surface of the earth and the moon.

1/2 mv^2 = mg(e)h (e) = mg(m)h(m)

gm= 1/6 g(e)

mg(e)h(e) = mg(m)h(m)

h(m)= g(e)/g(m) h(e)

h(m)= ge / 1/6ge h(e)

h(m)= 6* 4 ....as given

Therefore h(m) = 24

Hope this helps!