Question

An athlete complete one around if a circular track of diameter 200 m in 40 sec. what will be the distance covered and the dispacment at the and of 2 min 20 sec.
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Answer 1

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Answer 2

Explanation:

diameter = 200

radius = 100

circular track= 2πr

2×22/7×100

628.67

complete one round in 40s

628.67÷40=15.71675

2 min 20s = 120+20= 140s

15.71675×140= 2200.345

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