Question

an athlete complete one round of a circular track of diameter 49 in 20 s calculate the distance coveres and displacement at the end of 30 seconds​

Answer 1

Answer:

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your answer is here !

Explanation:

Given time = 30s

Time taken to complete one round = 20s

So,total rounds completed in 30s = 30/20 = 3/2 = 1.5

Given:diameter = 49

therefore radius = 49/2  and pi = 3.14

Now distance travelled in one round = 2*pi*r = 2*3.14*49/2

= 3.14*49 = 153.86

thus,total distance travelled in 30s = 1.5*153.86 = 230.79m

To find the displacement,

the shortest distance between initial and final position in diameter = 49m

thus,displacement of an athlete completes one round of a circular track = 49m

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Answer 2

Answer:

Given time = 30s

Time taken to complete one round = 20s

So,total rounds completed in 30s = 30/20 = 3/2 = 1.5

Given:diameter = 49

therefore radius = 49/2  and pi = 3.14

Now distance travelled in one round = 2*pi*r = 2*3.14*49/2

= 3.14*49 = 153.86

thus,total distance travelled in 30s = 1.5*153.86 = 230.79m

To find the displacement,

the shortest distance between initial and final position in diameter = 49m

thus,displacement of an athlete completes one round of a circular track = 49m

HOPE IT WORKS

AND MARK AS BRAINLIEST........