Physics, asked by yoursisteronly53, 3 months ago

an athlete completes 5 rounds of a circular track of diameter 10 metre in 15 minutes. calculate velocity and speed of the athlete​

Answers

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
88

Given

  • Number of rounds = 5
  • Diameter = 10 m
  • Time = 15 min

To Find

  • Velocity & Speed of the athlete

Solution

☯ Velocity = Displacement/Time

  • Where displacement is the shortest distance between the starting & ending point

☯ Speed = Distance/Time

━━━━━━━━━━━━━━━━━━━━━━━━━

Velocity of the athlete :

➞ Velocity = Displacement/Time

  • Displacement = 0 m (as the initial & the final points are the same after 5 rounds)
  • Time = 15 min = 15 × 60 = 900 sec

➞ Velocity = 0/900

➞ Velocity = 0 m/s

━━━━━━━━━━━━━━━━━━━━━━━━━

Speed of the athlete :

➞ Speed = Distance/Time

  • Distance = Circumference = 2πr = {2 × 22/7 × 5}×5 = 157m
  • Time = 900 sec

➞ Speed = 157/900

➞ Speed = 0.174 m/s

∴ The velocity of the athlete us 0 m/s & his speed is 0.174 m/s


Anonymous: fantastic!
akansha21kk: yummy:)
akansha21kk: kidding
akansha21kk: .nop
angelgirlnew: not bad
EnchantedGirl: Nice..!!
Anonymous: Superb, Excellent answer ✌
Answered by shaktisrivastava1234
97

 \huge \fbox{ANSWER}

 \large \underline{ \underline{ \frak{ \color{red}Given:}}}

 \mapsto \sf{Numbers \:  of  \: rounds=5 rounds}

{ \mapsto \sf{Diameter \:  of  \: circular  \: track = 10m}}

 \mapsto \sf{Time=15min}

\large \underline{ \underline{ \frak{ \color{cyan}To \:  find:}}}

 \leadsto \sf{Velocity  \: and  \: Speed  \: of \:  athlete. }

\large \underline{ \underline{ \frak{ \color{peru}Formula \: used:}}}

 \dag{ \boxed {\rm{Velocity(v)= \frac{Displacement (S)}{Time(t)} }}}

 \dag{ \boxed{ \rm{Speed= \frac{Distance }{Time} }}}

\large \underline{ \underline{ \frak{ \color{blue}ᴀccording  \: to  \: Question:}}}

{ \dashrightarrow{\sf{Velocity(v)= \frac{Displacement (S)}{Time(t)} }}}

{ \dashrightarrow{\sf{Velocity(v)= \frac{0}{15 \times 60}m {s}^{ - 1}  }}}

{ \dashrightarrow{\sf{Velocity(v)= \frac{0}{900}m {s}^{ - 1}  }}}

{ \dashrightarrow{\sf{Velocity(v)= 0m {s}^{ - 1}  }}}

 \bf \underline{ᴛʜᴇɴ,}

{ \dashrightarrow{ \sf{Speed= \frac{Distance }{Time} }}}

{ \dashrightarrow{ \sf{Speed= \frac{2\pi r \times 5round }{900} m {s}^{ - 1} }}}

{ \dashrightarrow{ \sf{Speed= \frac{2 \times  \frac{22}{7}  \times  \frac{10}{2}   \times 5}{900} m {s}^{ - 1} }}}

{ \dashrightarrow{ \sf{Speed= \frac{157}{900}m {s}^{ - 1}  }}}

{ \dashrightarrow{ \sf{Speed= 0.174m {s}^{ - 1}  }}}

 \bf \underline{ʜᴇɴᴄᴇ,}

   \:  \:  \:  \:  \: \star{ \boxed {\rm{Velocity(v)= 0m {s}^{ - 1}  }}}

   \:  \:  \:  \:  \: \star{ \boxed {\rm{Speed= 0.174m {s}^{ - 1}  }}}

 \bf \underline{ɴᴏᴛᴇ:}

 \sf{Here,athlete  \: complete \:  his  \: 5rounds  \: on }

 \sf{the \:  circular \:  track  \: so  \: the \:  displacement  \: is }

 \sf{0m/s. }


Anonymous: brilliant ! :)
angelgirlnew: nice and colorful answers ❤
Similar questions
Math, 3 months ago