Question

An athlete completes one quarter part of circular track of radius R/2. Calculate distance and displacement​

Answer 1

Answer:

Explanation:

Distance travelled = 2πR/4

Given, radius = R/2

Distance travelled = (2πR/2)/4

= πR/4

Displacement = √(R/2)² + (R/2)²

= √(2R²/4)

= √R²/2

#BAL

Answer 2

Given: The Radius of the circular track is $\frac{R}{2}$

Distance travelled by an athlete is,

Circumference of circular track = $\frac{1}{4}.2\pi\frac{R}{2}$

                                                     $=\frac{\pi R}{4}$

Displacement $=\sqrt{(\frac{R}{2})^2+(\frac{R}{2})^2}$

$=\frac{1}{2}\sqrt{R^2+R^2}$

$=\frac{1}{2}\sqrt{2R^2}$

$=\frac{R}{2}\sqrt{2}$

$=\frac{R}{\sqrt{2}}$

#SPJ2