An athlete completes one round of a circular round of a circular track of diameter 200m in 40s. What will be the distance covered and the displacement at the end of 2 mins 20s? With steps plse..
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distance covered in one complete round ie., 40 sec.
= circumference of circle of diameter 200 m
= π 200 meters.
Distance covered in 2 mins 20 sec or 140 sec: = 200 π * 140/40 = 700 π meters
In 140 seconds, the athlete makes 3 complete rounds and runs for 20 secs after that.
in 40 secs, he runs a complete circle (covers 360°). So in 20 secs, athlete runs half-circle and covers 180°.
So at the end of 140 seconds, athlete is at the diametrically opposite end on the circular track.
The displacement = vector joining the initial position to the final position.
It magnitude = diameter = 200 meters.
= circumference of circle of diameter 200 m
= π 200 meters.
Distance covered in 2 mins 20 sec or 140 sec: = 200 π * 140/40 = 700 π meters
In 140 seconds, the athlete makes 3 complete rounds and runs for 20 secs after that.
in 40 secs, he runs a complete circle (covers 360°). So in 20 secs, athlete runs half-circle and covers 180°.
So at the end of 140 seconds, athlete is at the diametrically opposite end on the circular track.
The displacement = vector joining the initial position to the final position.
It magnitude = diameter = 200 meters.
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2
Answer:
Given :-
Diameter of circular track = 200 m
Radius, r = 200/2 = 100 m
Time taken by athlete to complete one round = 40 seconds.
To Find :-
Distance covered = ??
Displacement = ??
Formula to be used :-
Speed = Distance/Time
Circumference of circle = 2πr
Solution :-
2 min 20 seconds = 140 seconds
Number of rounds = 140/4 = 35
⇒ Distance covered = 35 × circumference
⇒ Distance covered = 35 × 2 × 22/7 × 100
⇒ Distance covered = 5 × 2 × 22 × 100
⇒ Distance covered = 22000 m
Hence, the distance covered at the end of 2 min 20 seconds is 22000 m or 22 km.
And displacement is 200 m as it return to initial position again.
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