An athlete completes one round of a circular track of diameter 100m in 15 second what will be the distance covered and the displacement at the end of 3min and 30 second
Answers
Explanation:
:Diameter of circular track (D) = 200 m
Radius of circular track (r) = 200 / 2=100 m
Time taken by the athlete for one round (t) = 40 s
Distance covered by athlete in one round (s) = 2π r
= 2 × ( 22 / 7 ) × 100
Speed of the athlete (v) = Distance / Time
= (2 × 2200) / (7 × 40)
= 4400 / 7 × 40
Therefore, Distance covered in 140 s = Speed (s) × Time(t)
= 4400 / (7 × 40) × (2 × 60 + 20)
= 4400 / (7 × 40) × 140
= 4400 × 140 /7 × 40
= 2200 m
Number of round in 40 s =1 round
Number of round in 140 s =140/40
=3 1/2
Hence, Displacement of the athlete with respect to initial position at x= xy
= Diameter of circular track
= 200 m
Answer:
HI there !!
Displacement is the shortest distance possible between initial and final position.
As the athlete is in circular motion , displacement is zero. [ THis is because , the initial and final position is the same ]
Distance covered in 1 round = Circumference of the circle
Circumference of the circle = 2πr
Diameter = 200 m
Radius = 100 m
Distance covered in 1 round[ 40 sec ] = 2 × 22/7 × 100 = 628.57 m
Distance covered in 1 sec = 628.57 ÷ 40 = 15.71 m
2min 20 sec = 140 sec
Distance covered in 140 sec = 15.71 × 140 = 2199.4 m
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