An athlete completes one round of a circular track of diameter 200m in 40s.what will be the distance covered and the displacement at the end of 2 minutes and 20 seconds
Answers
Answer:
DISTANCE = 2198 m and DISPLACEMENT = 200m
Explanation:
distance covered in 40 sec = 2πr (where r is the radius of circular track)
= 2 x 3.14 x 100
distance covered in 40 sec = 628m
converting 2 minutes and 20 seconds in seconds= (2 x 60 + 20)seconds
= 140 seconds.
we can write 140 seconds as 40 + 40 + 40 + 20
from this we can conclude that at the end of 2 min 20 sec the athlete has travelled 3 complete round and half round
so,
distance travelled = 3 x perimeter of circle + perimeter of semi circle
= 3 x 2πr + πr
= 3 x 2 x 3.14 x 100 + 3.14 x 100
= 1884 + 314
= 2198 metre
displacement covered = diameter of circle (as finally it has travelled semicircluar path)
= 200 m
HOPE IT HELPS
PLEASE MARK ME AS BRAINLIEST
Answer:
Distance covered=2200m
Displacement=200m
Explanation:
Diameter=200m
2×radius=diameter
Radius=200/2
R=100m
Time taken=2minutes 20 seconds
=2×60+20
=120+20
=140 seconds
For one complete revolution he takes 40 seconds,
So in 120 seconds he can complete 3 revolutions and in remaining 20 seconds he will complete half a revolution.
Since, displacement depends only on initial and final positions .
So, displacement=diameter (since his final position is straight opposite to his initial position)
DISPLACEMENT=200m
Since he had completed 3 and half revolutions,
For one complete revolution the distance travelled is 2πr.
For three revolutions it is 3×2πr=6πr
For final half revolution it is πr
So distance covered=6πr+πr=7πr
Distance covered=7×22/7×100
DISTANCE COVERED=2200m