Math, asked by akkannavarchetan, 9 months ago

an athlete completes one round of a circular track of diameter 200m in 40sec what will be the distance covered and displacement at the end of 2 min and 40 sec​

Answers

Answered by akshvidhate
3

Answer:

distance covered = 2512m, and Displacement = zero or no displacement.

Step-by-step explanation:

2 min and 40 sec = 120 + 40 = 160sec

radius (r) = d/2 = 200m/22 = 100m

Circumference of circular track = 2 x pie x r

= 2 x 3.14 x 100

= 628m

Therefore, an athlete covers 628m in 40sec,

Therefore, distance covered by him in one second = 628/40 = 15.7m

Distance covered at the end of 2 min and 40 sec is = 15.7 x 160

Distance covered at the end of 2 min and 40 sec is = 15.7 x 160= 2512m

He covered one round in 40sec Therefore he'll complete 160/40 = 4 rounds at the end and distance covered by him will be 628 x 4 = 2512m

Which is total distance covered at the end.

Therefore,

At the end of 2 min and 40 sec he will come back to same position where he started.

Therefore displacement will be zero.

I hope it helps you.

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