Question

an athlete completes one round of a circular track of diameter 200m in 40sec.what will the displacement at the end of 2minutes 20sec​

Answer 1

✯✯ QUESTION ✯✯

An athlete completes one round of a circular track of diameter 200m in 40sec.what will the displacement at the end of 2minutes 20sec..

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✰✰ ANSWER ✰✰

$Diameter=200m$

$Radius=\dfrac{Dia.}{2}$

$Radius=\cancel\dfrac{200}{2}⟹100m.$

$Time=2min. \:20sec.$

Since,the athlete covers the complete round in 40 seconds .In 2 minutes 20 seconds he will complete 3½ rounds.

$Distance=\dfrac{7}{2}×2πr$

$Distance=\dfrac{7}{2}×2×\dfrac{22}{7}×100$

$Distance=22×100$

$\large{\boxed{\bold{\bold{\green{\sf{Distance=2200mtrs.}}}}}}$

Answer 2

✰ Question ✰

⋄ An athlete completes one round of a circular track of diameter 200m in 40sec.what will the displacement at the end of 2minutes 20sec.

✰ Given:-

⋄ Diameter of circular track = 200m

∴ Radius (r) = 200/2 =100m.

and Time taken to complete one round =40s

✰ To Find :-

Displacement of athlete end of 140s????

✰ Solution :-

⋄ If he take 40s to complete one round.

∴ He complete 3.5 round in 140 sec.

⋄ The distance covered by athlete in 140s

=2πr×3.5

⋄ Distance = 2×3.14×100 ×3.5= 2200m.

➤ If he complete one round the the displacement is zero.

He completes 3.5 round .

∴The displacement of 3 round is Zero.

and for 0.5 round the displacement is 200m.

Hence the Distance covered by athlete is 2200m and Displacement is 200m.