Math, asked by wwwbabluktl, 10 months ago

An athlete completes one round of a circular track of diameter 200 metre in 40 seconds. what will be the distance covered and the displacement at the end of 2 minutes 20 second

Answers

Answered by StarrySoul
43

Given :

• An athlete completes one round of a circular track of diameter 200 metre in 40 seconds.

To Find :

• The distance covered and the displacement at the end of 2 minutes 20 second.

Solution :

Here,

Total time = 2 minutes 20 seconds

→ 2 × 60 seconds + 20 seconds

→ 120 seconds + 20 seconds

140 seconds

Now,

In 40 s,the no. of rounds completed = 1

So,

In 140 s,the no. of rounds completed = \sf\dfrac{1}{40}\: \times 140

In 140 s,the no. of rounds completed = 3.5

Distance covered in 3.5 rounds :

When diameter of the track is 200 m,radius will be 100 m

Now,

[Distance covered in 1 round = Circumference of the circle]

→ 2 × 22/7 × 100

→ 4400/7

628.57

Total Distance covered = 628.57 × 3.5 m

2200

\therefore Distance covered at the end of 2 minutes 20 seconds is 2200 m

Displacement covered in 3.5 rounds :

The athlete makes three and a half rounds now If the athlete starts from point A,then after completion of 3 rounds he'll be at the point A again. And when again start from point A and makes the remaining half round, he'll reach point B. So,the displacement of athlete will be equal to diameter of the circular track (Point B is diametrically opposite to point A)

\therefore Displacement covered at the end of 2 minutes 20 seconds is 200 m.

Refer to the attachment!

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