Physics, asked by ayisha8006, 10 months ago

An athlete completes one round of a circular track of diameter 50 m in 30 s. find distance travelled and displacement of the athlete at the end of 30 s.

Answers

Answered by shivanshverma056
18

Answer:

ANSWER

The diameter of the circular track is given as 200 m. That is, 2r=200 m.

From this radius is calculated as Radius, r = 100 m.

In 40 sec the athlete complete one round. So, in 2 mins and 20 secs, that is, 140 sec the athlete will complete = 140 / 40 = 3.5 (three and a half) rounds.

One round is considered as the circumference of the circular track.

The distance covered in 140 sec = 2πr×3.5=2×3.14×100×3.5=2200 m.

For each complete round the displacement is zero. Therefore for 3 complete rounds, the displacement will be zero.

At the end of his motion, the athlete will be in the diametrically opposite position. That is, displacement = diameter = 200 m.

Hence, the distance covered is 2200 m and the displacement is 200 m.

Explanation:

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Answered by Anonymous
13

Answer:

Distance = 157 m

Displacement = 0 m

Explanation:

Given:

  • Diameter of the circular track = 50 metres
  • Time taken to cover one round of the circular track = 30 seconds

To find:

  • Distance at end of 30 seconds
  • Displacement at end of 30 seconds

Distance:

As 1 round takes 30 seconds and we have to find distanec at the end of 1 seconds, the circumference of the circle is equal to distance

Circumference of circle = 2 \pi r

Radius = \frac{Diameter}{2}

Radius = 25 m

Circumference = 2 \times 3.14 \times 25

Circumference =6.28 \times 25

Circumference = 157 metres

The distance travelled by the athlete at the end of 30 seconds is 157 metres

Displacement:

At the end of 30 seconds the athlete will reach back to the initial position, so the displacement will be equal to 0

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