An athlete completes one round of a circular track of diameter 40 m in 12 s. What will be his distance n displacement at end of 42 s.
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3
Explanation:
Displacement= straight line from a to b
=diameter of circle
=200 m
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0
Answer:
The person takes 12 seconds to complete 1 round.
42 = 12 + 12 + 12 + 6
So at the end of 42 seconds he will have completed 3 full and 1 half circle.
So he will be at the point diametrically opposite to the point from where he started at t = 0.
So, displacement = 2R = D = 40m
Now, R=20m
Distance = 3 Full circles + 1 half circle
= 3x2x?xR + ?xR = 7x?xR = 22x20 = 440m is the distance.
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