An athlete completes one round of a circular track of diameter 200m in 40sec. what will be the distance and displacement at the end of 2min 20sec.
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Speed = distance/time
Distance = circumference of the track.
Distance = 200xπ
Speed =200xπ/40
Speed = 5π
time = 2 min 20s = 140s
distance = 140*5*π
distance = 700π
∴distance=700π
One round of the circular track = 200π
700π/200π=3.5
So the athlete completes 3.5 rounds.
The distance between the athlete and his starting point along the track is 0.5 rounds, or a semicircle.
The displacement will be the chord connecting the two points.
The chord of a semi circle is the diameter.
Diameter = 200m.
∴displacement=200m
Distance = circumference of the track.
Distance = 200xπ
Speed =200xπ/40
Speed = 5π
time = 2 min 20s = 140s
distance = 140*5*π
distance = 700π
∴distance=700π
One round of the circular track = 200π
700π/200π=3.5
So the athlete completes 3.5 rounds.
The distance between the athlete and his starting point along the track is 0.5 rounds, or a semicircle.
The displacement will be the chord connecting the two points.
The chord of a semi circle is the diameter.
Diameter = 200m.
∴displacement=200m
pari166:
for distance we can find by the formula of circumference of circle
listen 200π is the distance of 1 sec. ...for 40 sec we have to find the speed
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