Question

An athlete completes one round of a circular track of diameter 210 m in 40 seconds with

uniform speed.

a) Name the type of motion performed by athlete.

b) Calculate the distance covered at the end of 2 minutes.

c) Find the displacement of athlete at the end of 2 minutes.

d) Calculate the speed of the athlete.​

Answer 1

Answer:

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Answer 2

The diameter of the circular track is given as 200 m. That is, 2r=200 m.

From this radius is calculated as Radius, r = 100 m.

In 40 sec the athlete complete one round. So, in 2 mins and 20 secs, that is, 140 sec the athlete will complete = 140 / 40 = 3.5 (three and a half) rounds.

One round is considered as the circumference of the circular track.

The distance covered in 140 sec = 2πr×3.5=2×3.14×100×3.5=2200 m.

For each complete round the displacement is zero. Therefore for 3 complete rounds, the displacement will be zero.

At the end of his motion, the athlete will be in the diametrically opposite position. That is, displacement = diameter = 200 m.

Hence, the distance covered is 2200 m and the displacement is 200 m.