Question

an athlete completes one round of a circular track of diameter 14 m in 20 seconds calculate the distance covered and displacement at the end of 30 seconds

Answer 1

$using \: proportioal \\ let \:the \: dispalacement \: be \: \: x\\ = > \frac{14}{20} = \frac{x}{30} \\ = > 14 \times 30 = 20 x \\ = > x = \frac{14 \times 30}{20} \\ = > x = 21m \: \\ hope \: it \: will \: help \: you$