an athlete completes one round of a circular track of diameter 49 metre in 20 seconds calculate the distance covered and displacement at the end of 30 seconds
Answers
Answered by
19
Howdy !!
your answer is ---
Given , diameter of circular path = 49m
so, radius r = 49/2 m
now , distance covered by athlete
= 2πr = 2 × 22/7 × 49/2
= 154 m
so, athlete covered 154 m in 20 sec
now, at 30 second
the athlete covered πr of circle
so, displacement = diameter of circular pat
therefore , displacement = 49m
hence, distance = 154 m &
displacement = 49 m
hope it help you
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your answer is ---
Given , diameter of circular path = 49m
so, radius r = 49/2 m
now , distance covered by athlete
= 2πr = 2 × 22/7 × 49/2
= 154 m
so, athlete covered 154 m in 20 sec
now, at 30 second
the athlete covered πr of circle
so, displacement = diameter of circular pat
therefore , displacement = 49m
hence, distance = 154 m &
displacement = 49 m
hope it help you
==========✌✌✌✌✌✌✌✌============
Attachments:
pdpatel1:
thanks
Answered by
6
Circumference of track = 22/7 x 49 = 154
So he runs 154 m in 20 sec
Therefore 1 sec = 154/20 = 7.7 m
Therefore 30 sec = 7.7 x 30 = 231 m
So Distance covered = 231 meters
Therefore displacement = 231 - 154 = 77 meters
hope it help youu.....
:-D
So he runs 154 m in 20 sec
Therefore 1 sec = 154/20 = 7.7 m
Therefore 30 sec = 7.7 x 30 = 231 m
So Distance covered = 231 meters
Therefore displacement = 231 - 154 = 77 meters
hope it help youu.....
:-D
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