An athlete completes one round of a circular track of radius R in 40 sec. What will be s displacement at the end of 2 min 20 seconds?
Answers
Answered by
5
Hi.
Here is the answer---
________________
Time taken by the Athlete to complete one round = 40 seconds.
Thus, Number of Rounds completed in 2 minutes (120 seconds) = 120/40
= 3 rounds.
Thus, Displacement covered by the Body in 3 rounds = 0
[Since, body returned to the same point]
Now, In remaining 20 seconds, number of rounds covered will be 20/40 round = 1/2 Round.
In One Round, Distance Covered = 2 × × r
= 2 × (22/7) × R
= 44R/7
Thus, Displacement covered in (1/2) Round = (1/2)(44R/7)
= (22/7)R
= R
________________
Hope it helps.
Here is the answer---
________________
Time taken by the Athlete to complete one round = 40 seconds.
Thus, Number of Rounds completed in 2 minutes (120 seconds) = 120/40
= 3 rounds.
Thus, Displacement covered by the Body in 3 rounds = 0
[Since, body returned to the same point]
Now, In remaining 20 seconds, number of rounds covered will be 20/40 round = 1/2 Round.
In One Round, Distance Covered = 2 × × r
= 2 × (22/7) × R
= 44R/7
Thus, Displacement covered in (1/2) Round = (1/2)(44R/7)
= (22/7)R
= R
________________
Hope it helps.
Answered by
1
Answer:
answer =2R
Explanation:
Time to complete one revolution =40 sec
Total time =2x60+20 = 140 sec
no. of revolution = Three and half
Therefore, displacement =2R
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