Question

an athlete completes one round of a circular track of radius 40 second what will be distance travelled and magnitude of displacement at the end of 2 minutes 20 seconds​

Answer 1

Answer:

One round = 2πr

R is equal to d upon 2= 200 upon 2= 100

Total time is equal to 2 minute 20 second

=2x60+20=140s

Number of round = total time upon time for one round

= 140 upon 40 is equal to 3.5 rounds

. Distance is equal to number of round into length of 1 round

3.5 upon 10 into 628 into 2 into 22 upon 7 into 100

Is equal to 10 into 22 into 10

Is equal to 2200 distance and displacement is equal to shortest distance that is 200 metre