An athlete completes one round of a square track whose area is 400 sq.
meter in 45 s. What will be the distance covered, Average speed and the
displacement at the end of 2 minutes 15 s?
Answers
Given :-
Area of the circular track = 400 m
Time taken to complete one round = 45 sec
To Find :-
The average speed.
The displacement at the end of 2 min 15 sec.
Analysis :-
Firstly find the number of rounds completed by the athlete accordingly.
Then the total distance covered accordingly.
Finally to find the average speed, substitute the values accordingly such that speed is equal to total distance divided by time taken.
Solution :-
We know that,
- s = Side
- a = Area
- t = Time
- p = Perimeter
- d = Displacement
- v = Speed
Finding the number of rounds,
Given that,
Time (t) = 2 min 15 sec = 135 sec
Time taken to complete one round = 45
Substituting their values,
⇒ 135/45
⇒ 3 rounds
Using the formula,
Given that,
Area (a) = 400 m²
Substituting their values,
⇒ s × s = 400
⇒ s² = 400
⇒ s = √400
⇒ s = 20 m
Using the formula,
Given that,
Side (s) = 20 m
Substituting their values,
⇒ p = 4s
⇒ p = 4 × 20
⇒ p = 80 m
Number of rounds = 3
⇒ 3 × 80
⇒ 240 m
Using the formula,
Given that,
Distance (s) = 240 m
Time (t) = 45 sec
Substituting their values,
⇒ s = d/t
⇒ s = 240/45
⇒ s = 5.33 m/s
Therefore,
Average speed = 5.33 m/s
Distance at the end of 2 min 15 sec = 240 m
Answer:
Given :-
- Area of square track = 400 m²
- Time taken to cover = 45 s
To Find :-
Distance covered, Average speed and the displacement at the end of 2 minutes 15 s?
Solution :-
Firstly let's found total round covered
135/4 = 33.75 rounds
Radius = Diameter/2
Radius = 400/2
Radius = 200 cm
Now,
33.75 × 2 × 22/7 × 200
67.5 × 22 × 100 / 7
67.5 × 2200 / 7
148500 / 7
21214.2 m
Average speed = Total Displacement/Time taken
Average speed = 21214.2/45
Average speed = 157.14 m/s