Question

An athlete completes one round of circular track of diameter 49m in 20 sec .Calculate the distance and displacement at the end of 30s.

Answer 1

Explanation:

• Distance travelled in 20 sec=2 pie r
• 20 sec=154
• 1sec=154/20=7.7cm.

• 1 sec=7.7cm
• 30 sec =7.7x30=231cm.

So at the end of 30 sec distance travelled will be 231cm.

Now ,in 20 sec he can complete 1 round ,so in 30 sec he will complete 1/2 round .

So displacement will be =1/2 pie r

=1/2×22/7×49/2=38.5 cm

So displacement is equal to 38.5 cm .

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