An athlete completes one round of circular track of diameter 200m in 4 sec. what will be the distance covered and the displacement at the end of 2 minutes 20 seconds?
Answers
200 m
Diameter of circular track = 200 m
Radius, r = 200/2 = 100 m
Time taken by athlete to complete one round = 40 seconds.
Formula to be used :-
Circumference of circle =
2 min 20 seconds = 140 seconds
Number of rounds = 140/4 = 35
⇒ Distance covered = 35 × circumference
⇒ Distance covered = 35 × 2 × 22/7 × 100
⇒ Distance covered = 5 × 2 × 22 × 100
⇒ Distance covered = 22000 m
Hence,
the distance covered at the end of 2 min 20 seconds is 22000 m or 22 km.
And displacement is 200 m as it return to initial position again.
✬ Distance = 2200 m ✬
✬ Displacement = 200 m ✬
Explanation:
Given:
- Diameter of circular track is 200 m.
- Time take by athlete to cover 200 m is 4 seconds.
To Find:
- Distance covered and displacement at the end of 2 minutes 20 seconds.
Solution: Diameter of track is 200 m therefore,
➟ Radius of track = d/2 = 200/2 = 100 m
➟ Time taken to cover 1 round = 40 seconds and Total time taken 2 minutes 20 seconds.
• 1 min = 60 seconds
∴ 2 min 20 sec = 2(60) + 20
=> 140 seconds.
Distance covered by athelete in one round will be equal to the circumference of circle.
★ Circumference of circle = 2πr ★
Distance covered = 2π(100)
Distance covered = 200π
Thus,
- Distance covered in 40 sec = 200π or Distance covered in 1 sec = 200π/40 = 5π
∴ Distance covered in 140 seconds = 140 5π
➭ 700π
➭ 700 22/7
➭ 100 22
➭ 2200 m
Hence, Distance covered at the end is 2200 m.
[ Now, Displacement ]
- It is given that athelete take 40 sec to cover one round and he ram for 220 seconds.
∴ Total rounds = Total distance covered/Distance covered in one round
➨ 700π/200π
➨ 3.5 rounds.
Therefore, if he started from point A after 140 seconds he will be at point B.
Hence, Displacement = Point A to B
➨ 100 + 100
➨ 200 m.