an athlete completes one round of circular track of diameter 200m in 40 seconds calculate the total distance covered by athletes in 1 round
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Answer:
An athlete completes one round of a circular track of a diameter of 200m in 40s. What will be the distance covered and the displacement at the end of 2 min 20s?
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Distance is defined as a complete path traveled by an object. Displacement is defined as the shortest distance between two points
Answer: Distance covered by the athlete to complete a circular track of a diameter 200m at the end of 2 min 20 seconds is 2200m or 22km and displacement is 200 m
Let's understand the given problem
Explanation:
Given : Diameter of circular track = 200 m
Radius 'r' = 200/2 = 100 m
Time taken by the athlete to complete one round of circular track = 40 seconds
Now,
Time = 2 min 20s = 2 × 60 + 20 = 140 seconds (Since, 1 minute = 60 seconds)
Number of rounds covered by the athlete = Total time / Time taken to complete one round
= 140/40 = 3.5
Circumference of a circle = 2πr
Distance covered in 1 round = Circumference of the circular track
Thus, circumference of the circular track = 2 × 22/7 × 100
Distance traveled in 140 seconds = Number ofLet the athlete start from point A and reache point B after 140s
Thus, the displacement will be equal to the length of the line segment AB
Lebgth of AB = Diameter of the circle = 200m
Thus, Displacement of the athlete is 220m rounds covered × Circumference of the track
= 3.5 × 2 × 22/7 × 100
= 0.5 × 2 × 22 × 100
Thus, Distance covered = 2200m
Now, to calculate the displacement let's look into the below diagram
Answer:
Explanation:
Given :-
Diameter of circular track = 200 m
Radius, r = 200/2 = 100 m
Time taken by athlete to complete one round = 40 seconds.
To Find :-
Distance covered = ??
Displacement = ??
Formula to be used :-
Speed = Distance/Time
Circumference of circle = 2πr
Solution :-
2 min 20 seconds = 140 seconds
Number of rounds = 140/40 = 3.5
⇒ Distance covered = 3.5 × circumference
⇒ Distance covered = 3.5 × 2 × 22/7 × 100
⇒ Distance covered = 5 × 2 × 22 × 100
⇒ Distance covered = 2200 m
Hence, the distance covered at the end of 2 min 20 seconds is 2200 m.
And displacement is 200 m as it return to initial position again.