An athlete completes one round of circular track of radius r in 30s with uniform speed. The ratio of distance to the displacement travelled by the athlete at the end is 45s is 3/2pie ? how
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Answered by
19
Let uniform speed is V
ATQ
2πr = v×30
Therefore, V= 2πr/30
Let A be the initial point for the athlete . So, after 45 seconds, he will reach at point B
Therefore, Distance covered in 45sec = 2πr/30× 45
= 3πr
Displacement covered in 45sec = AB = 2r
Distance/Dispacement = 3πr/2r
= 3/2π
ATQ
2πr = v×30
Therefore, V= 2πr/30
Let A be the initial point for the athlete . So, after 45 seconds, he will reach at point B
Therefore, Distance covered in 45sec = 2πr/30× 45
= 3πr
Displacement covered in 45sec = AB = 2r
Distance/Dispacement = 3πr/2r
= 3/2π
Answered by
2
in 30 second his displacement is zero
distance =2pir
and now in next 15 seconds he will cover half circle more
displacement is 2r
distance= 2*pi*r+pi*r=3*pi*r
so you can find the ratio
distance =2pir
and now in next 15 seconds he will cover half circle more
displacement is 2r
distance= 2*pi*r+pi*r=3*pi*r
so you can find the ratio
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