An athlete completes one round safe circular track of dia. 200m in 40s. Find distance and displacement at the the end of 2 minutes 20seconds
Answers
Answered by
1
Circumference of the circle = 2πr
Diameter = 200 m
Radius = 100 m
Distance covered in 1 round[ 40 sec ] = 2 × 22/7 × 100 = 628.57 m
Distance covered in 1 sec = 628.57 ÷ 40 = 15.71 m
2min 20 sec = 140 sec
Distance covered in 140 sec = 15.71 × 140 = 2199.4 m
hope it help u
Diameter = 200 m
Radius = 100 m
Distance covered in 1 round[ 40 sec ] = 2 × 22/7 × 100 = 628.57 m
Distance covered in 1 sec = 628.57 ÷ 40 = 15.71 m
2min 20 sec = 140 sec
Distance covered in 140 sec = 15.71 × 140 = 2199.4 m
hope it help u
Allen27:
The answer is not the same as the one given in the book can you do it in an other method
Answered by
1
Distance =200m
In 40s----------200m
So,
In 1 s----------200/40=>5m/s
And in 2min 20sec(or 140s)
In 1s-------5m/s
So,
In 140s---------140×5=>700m/s
And displacement is zero since athlete came at the same distance from where he started
In 40s----------200m
So,
In 1 s----------200/40=>5m/s
And in 2min 20sec(or 140s)
In 1s-------5m/s
So,
In 140s---------140×5=>700m/s
And displacement is zero since athlete came at the same distance from where he started
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