Question

An athlete covers three and a half round of a circular path of 35 meters in 140 second find its displacement and velocity

Answer 1

Answer:

Displacement = 70 metres

Velocity =0.5 m/s

Explanation:

Given :

Radius of the circular path = 35 metres

Time taken to complete three and half rounds = 140 seconds

To find :

• Displacement

• Velocity

Circumference of the circular path = 2×3.14×35=219.8 metres

Velocity = Displacement / time

At the end of 3½ rounds Displacement will be equal to the diameter of the circular path

Displacement = 2×35 = 70 metres

Velocity = 70/140

Velocity = 0.5 m/s

The Displacement is 70 metres and velocity is equal to 0.5 m/s

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{displacement = 70 \: meter}}}$

$\green{\tt{\therefore{velocity = 0.5 \: \: m/s}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}}$

$\tt: \implies An \: athlete \: covers \: three \: and \: a \: half \:$

$\tt: \implies round \: of \: a \: circular \: path \: of \: 35 \: meters \: in \: 140 \: second$

$\red{\underline \bold{To \: Find:}}$

$\tt: \implies find \: its \: displacement \: and \: velocity$

• Given Question

$\tt \circ circumference \: of \: circular \: path = 2 \times 3.14 \times 35 = 219.8$

$\bold{velocity = displacement/time}$

$\tt: \implies in \: the \: the \: end \: of \: \: 3\frac{1}{2} \: round$

$\tt: \implies dicplacement \: will \: equal \: to \: diameter \: in \: the \: circular \: path$

$\tt: \implies displacement = 2 \times 35 = 70 \: metres$

$\tt: \implies velocity = \frac{70}{140}$

$\tt: \implies velocity = 0.5 \: \: m</strong><strong>$

$\tt: \implies velocity = 0.5 \: \: m/s$

$\green{\tt{\therefore{displacement = 70 \: meter}}}$

$\green{\tt{\therefore{velocity = 0.5 \: \: m/s}}}$