An athlete has taken 100 g glucose of energy equivalent to 1560 kJ. He utilizes 50% of this gained energy in an
event. In order to avoid storage of energy in the body, calculate the mass of water he would need to perspire.
(Enthalpy of H2O for evaporation = 44 kJ mol 1)
(A). 346 g
(B). 316 g
(C) 323 g
(D). 3199
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Answer:
B . 316 gm
Explanation:
upon utilizing 50% energy , energy to be stored = 780 kJ
enthalpy of H20 vaporization = 44 kJ /mol
No of moles of vaporized water = 780 / 44 = 17.7 mol
Mass of 1 mol of water = 18 g
mass of 17.7 mol water = 17.7 × 18 = 316 g (approximately)
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