Question

An athlete is given 180g of glucose. he utilises 50% of the energy due to internal combustion in the body. in order to avoid storage of energy in the body,calculate the mass of water he would need to perspire. given enthalpy of combustion of glucose is -2800 kj mol^-1 and enthalpy of evaporation of water is 44 kj mol^-1.

Answer 1

Yeah...here you go!!!

Hope it helps!!

Answer 2

Answer:

Answer is 572.7 gm

Step-by-step explanation:

180 g of glucose has enthalpy of combustion =2800kJ/mol

Energy utilised=50/100×2800=1400kJ/mol

Energy left=2800-1400=1400kJ/mol

.•. Energy to be given out as respiration to avoid storage of energy=1400kJ/mol

g h2o. Energy h2o.

18g 44kJ/mol

xg. 1400kJ/mol

x=18×1400/44

x=572.7 g

572.7 g amount of heat to be perspired