Question

An athlete jumps at an angle of 30 degree with a maximum speed of 9.4 m/s. The range covered by him in the above jump is .............. hint: use Range R, equation

Answer 1

Explanation:

The equation of motion says:

v=u+at

Considering only the vertical component of his jump we can get the time it takes to reach his maximum height from:

0=uy−gt

usinθ=uy which is the vertical component of his initial velocity u.

∴0=usinθ−gt

∴t=usinθg

Since θ=23 this becomes:

t=4sin239.8=0.159s

The 2nd part of his journey as he falls to earth is a mirror image of the first part so:

t=2×0.159=0.32s

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