Question

An athlete moves complete two rounds around a circular track of radius 7m in 20
seconds calculate (a) distance (b) displacement (d) speed.

Answer 1

Answer:

Distance = 88 meters

Displacement = 0

Speed = 4.4 m/s

Step-by-step explanation:

Answer 2

Answer:

(a) 88m

(b) 0m

(c) 4.4 m/s

Step-by-step explanation:

Round taken by athlete = 2

Radius = $7m$

Time taken = $20sec$

(a) distance

Distance travelled will be 2*circumference of the circular path

$Dist=2*2\pi r$

$Dist = 2*2*\frac{22}{7} *7$

$Dist = 2*2*22$

$Dist=88m$

(b) Since the athlete comes back to the same initial position from which he started, difference in starting and ending position becomes null, thus displacement is 0.

(c) Speed = Dist / Time

$Speed = \frac{88}{20}$

$Speed=4.4m/s$

Thus the athlete completes two rounds around the circular track with a speed of 4.4 m/s.