an athlete moves on a rectangular track having dimensions are 400 *300m he completed one round in 60s what will be the speed and velocity if he moves on track for 2.5 min.
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perimeter of rectangle = 2*(l + b)
perimeter=2*(400+300)
=1400meter
hence speed=1400/60m/s=23.33sec
in 2.5 min = 2.5*60 sec
= 150 sec
no. of round= 150/603
hence travelled distance=(150/60)*1400
= 3500 meter
hence after 2nd round travelled distance=
3500-2800=700 meter
because it makes right angled∆
now displacement=√[(300)²+(400)²]
=√[90000+160000]
=√[250000
= 500meter
velocity= 500/150 =3.33m/s
perimeter=2*(400+300)
=1400meter
hence speed=1400/60m/s=23.33sec
in 2.5 min = 2.5*60 sec
= 150 sec
no. of round= 150/603
hence travelled distance=(150/60)*1400
= 3500 meter
hence after 2nd round travelled distance=
3500-2800=700 meter
because it makes right angled∆
now displacement=√[(300)²+(400)²]
=√[90000+160000]
=√[250000
= 500meter
velocity= 500/150 =3.33m/s
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