an athlete running with uniform speed along a circular track of radius 42m complete one round in 40 seconds. calculate average speed and average velocity in time interval of (1) 0-10sec (2) 0-20sec (3) 0- 40sec
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circumference of circle=2 pir
= 2*22/7*42
= 44*6
= 264m
now, speed= 264/40= 6.6m/s
1) Average spped between 0-10 sec= 264/4
= 66/10= 6.6m/s
&,, displacement ≈ 60m [using Pythagoras theorm]
so, velocity= 60/ 10=6m/s
2) Average speed between= 0-20 sec. =
264/2
= 132/20= 6.6m/s
& Averge velocity= 84/20= 4.2 m/s
3) Average speed between 0-40 sec.
= 264/40= 6.6m/s
& Aveage velocity= 0/40= 0m/s
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= 2*22/7*42
= 44*6
= 264m
now, speed= 264/40= 6.6m/s
1) Average spped between 0-10 sec= 264/4
= 66/10= 6.6m/s
&,, displacement ≈ 60m [using Pythagoras theorm]
so, velocity= 60/ 10=6m/s
2) Average speed between= 0-20 sec. =
264/2
= 132/20= 6.6m/s
& Averge velocity= 84/20= 4.2 m/s
3) Average speed between 0-40 sec.
= 264/40= 6.6m/s
& Aveage velocity= 0/40= 0m/s
________________
hope it helps☺
✌✌
Read more on Brainly.in - https://brainly.in/question/3607996#readmore
Answered by
3
Answer:
an athlete running with uniform speed along a circular track of radius 42m complete one round in 40 seconds. calculate average speed and average velocity in time interval of (1) 0-10sec (2) 0-20sec (3) 0- 40sec
Explanation:
0/m/s
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