Question

An athlete runs 600 m in 2 minutes and the next 1000 m in 1 minute on the same straight
path. What is his average speed and average velocity

Answer 1

Provided that:

• An athlete runs 600 m in 2 minutes and the next 1000 m in 1 minute on the same straight path.

To calculate:

• His average speed and average velocity respectively.

Solution:

• His average speed and average velocity are ${\sf{8.\bar{8}}}$ ≈ 8.9 m/s and no displacement respectively.

Using concepts:

• Average speed formula
• Average velocity formula
• Formula to convert min into s

Using formulas:

• ${\small{\underline{\boxed{\sf{v \: = \dfrac{s}{t}}}}}}$

Where, v denotes the average speed, s denotes the total distance, and t denotes the total time

• ${\small{\underline{\boxed{\sf{a_{av} \: = \dfrac{s}{t}}}}}}$

Where, a_av denotes the average velocity, s denotes the displacement, and t denotes the total time.

• ${\small{\underline{\boxed{\sf{1 \: minute \: = 60 \: seconds}}}}}$

Required solution:

~ Firstly let us convert minutes into seconds by using suitable formula!

Converting 2 minutes into seconds!

$:\implies \sf 1 \: minute \: = 60 \: seconds \\ \\ :\implies \sf 2 \: minute \: = 2 \times 60 \: seconds \\ \\ :\implies \sf 2 \: minute \: = 120 \: seconds$

Converting 1 minute into seconds!

$:\implies \sf 1 \: minute \: = 60 \: seconds$

~ Now let us find out total time taken!

$:\implies \sf Total \: time \: = 1st \: time \: + 2nd \: time \\ \\ :\implies \sf Total \: time \: = 120 + 60 \\ \\ :\implies \sf Total \: time \: = 180 \: seconds$

~ Now let us find out total distance!

$:\implies \sf Total \: distance \: = 1st \: distance \: + 2nd \: distance \\ \\ :\implies \sf Total \: distance \: = 600 + 1000 \\ \\ :\implies \sf Total \: distance \: = 1600 \: metres$

~ Now let's find out the average speed!

$:\implies \sf v \: = \dfrac{s}{t} \\ \\ :\implies \sf v \: = \dfrac{1600}{180} \\ \\ :\implies \sf v \: = \dfrac{160}{18} \\ \\ :\implies \sf v \: = \dfrac{80}{9} \\ \\ :\implies \sf v \: = 8.\bar{8} \: ms^{-1} \\ \\ :\implies \sf Average \: speed \: = 8.\bar{8} \: ms^{-1}$

~ Now let's talk about displacement!

↪️ According to the given question I don't think so that he have displacement as it is said that he moved 600 m first then 1000 m on a same straight path but it is not said that he stop or not, he moved to initial postion again or not, he moved to any other backward position or not. That's why he haven't any displacement

Answer 2

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