Question

an athlete runs a distance of 1500 M starting from rest accelerates himself uniformly at 2 metre per second square till he covers a distance of 900 M he then runs the remaining distance of 600 M at a uniform speed developed calculate the time taken by the athlete to covers to two parts of the distance covered also find the time when he is at the centre of the track​

Answer 1

Hope so this will help you out : ))

Answer 2

Answer:

60 seconds

Explanation:

u = 0 For the first 900 metre , a = 2m/s2 , u = 0 since, v2 – u2 = 2as v2 = 2 × 900 × 2 = 3600 so, v = 60 m/s also, v = u + at 60 = 0 + 2t t = 30 sec so, time taken to complete first 900 m is 30 seconds For the second 900 m, v = 30m/s (uniform throughout) , time = 900/30 = 30 sec. so, time taken to complete 2nd 900m = 30 sec. Total time taken = 60 seconds.(to travel 1800m)