An athlete runs from one end to the other end of a semi circular track whose radius is 70m. what is the distance covered by the athlete and what is his displacement?
Answers
Answered by
1
Answer:
2pi radius= circumference
2 x pi x 70 = 439.8m
semicircle = half a circle
0.5 x 439.8 = 219.9m
displacement should be 2 x the radius, aka the diameter. The start and end position intersect the "circle" because it's a semi circle.
2 x 70 = 140m
Explanation:
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Answered by
0
Given:
it's a semi circular track having radius 70m.
so the distance covered will be the perimeter of the semi circle.
perimeter = πr + 2r
= 22/7× 70 + 2×70
= 220 + 140
= 360m
displacement will be the shortest distance covered, that is the diameter of the semicircle.
So, diameter = 2×70
= 140m
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