An athlete runs on a track with a velocity of 20 km/hr and jumps into a car of mass 50 kg standing on the track. Calculate the velocity with which the car will start moving along the track, if the weight of the athlete is 50 kg.
PLEASE ANSWER FAST... I HAVE EXAM TMRW
Answers
Answered by
0
Answer:
v = 1.875 m/s
Explanation:
Mass of man (m1) = 60kg
Initial velocity of man (u1) = 18 km/h=18x5/18=5m/s
Final velocity of man (v1) = (v2) = v
Mass of car (m2)= 100kg
Initial velocity of car (u2) = 0 (as it is in rest)
Final velocity of car (v2) = v
According to law of conservation of momentum,
m1u1 +m2u2 = m1v1 + m2v2
60x5 + 100x0 = 60 x v + 100 x v
300+0 = 160v
v = 300/160
v = 1.875 m/s
Answered by
1
Answer:
v = 2.78 m/s
Explanation:
`the velocity of athlete [u 1] =20 km/h = 5.56 m/s
the mass of athlete [m 1] = 50 kg
the velocity of car [u 2] = 0
mass of car [m 2] = 50 kg
m 1 u + m 2 u = m 1 v + m 2 v
50*5.56 + 50*0 = 50* v + 50*v
278 + 0 = 50v +50v
278 = 100v
v= 278/100
v = 2.78 m/s
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