Question

An athlete runs with speed 12 m/s . Determine the longest jump he can undertake

Answer 1

From the formula of Horizontal Range (R) = u*2sin 2A/g.

Now to maximise the range we can take the maximum value of sin theta which is 1. The maximum range for a given velocity of projection will be when sin 2A = 1, that is, when 2A = 90degree or when A = 45 degree.

Therfore, Range (R) = u*2/g; where g = acceleration due to gravity = 9.8m/s^2

or, R = 12^2 / 9.8 = 144/9.8 metre. = 14.6938 metre.